Optimal. Leaf size=361 \[ \frac {2 b \left (-3 a^2 d^2+6 a b c d-\left (b^2 \left (4 c^2-d^2\right )\right )\right ) \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{3 d^2 f \left (c^2-d^2\right )}-\frac {2 b \left (-9 a^2 d^2+18 a b c d-\left (b^2 \left (8 c^2+d^2\right )\right )\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} F\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{3 d^3 f \sqrt {c+d \sin (e+f x)}}-\frac {2 \left (-3 a^3 d^3+9 a^2 b c d^2-9 a b^2 d \left (2 c^2-d^2\right )+b^3 \left (8 c^3-5 c d^2\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{3 d^3 f \left (c^2-d^2\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}+\frac {2 (b c-a d)^2 \cos (e+f x) (a+b \sin (e+f x))}{d f \left (c^2-d^2\right ) \sqrt {c+d \sin (e+f x)}} \]
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Rubi [A] time = 0.62, antiderivative size = 361, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.259, Rules used = {2792, 3023, 2752, 2663, 2661, 2655, 2653} \[ \frac {2 b \left (-3 a^2 d^2+6 a b c d+b^2 \left (-\left (4 c^2-d^2\right )\right )\right ) \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{3 d^2 f \left (c^2-d^2\right )}-\frac {2 b \left (-9 a^2 d^2+18 a b c d+b^2 \left (-\left (8 c^2+d^2\right )\right )\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}} F\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{3 d^3 f \sqrt {c+d \sin (e+f x)}}-\frac {2 \left (9 a^2 b c d^2-3 a^3 d^3-9 a b^2 d \left (2 c^2-d^2\right )+b^3 \left (8 c^3-5 c d^2\right )\right ) \sqrt {c+d \sin (e+f x)} E\left (\frac {1}{2} \left (e+f x-\frac {\pi }{2}\right )|\frac {2 d}{c+d}\right )}{3 d^3 f \left (c^2-d^2\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}+\frac {2 (b c-a d)^2 \cos (e+f x) (a+b \sin (e+f x))}{d f \left (c^2-d^2\right ) \sqrt {c+d \sin (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 2653
Rule 2655
Rule 2661
Rule 2663
Rule 2752
Rule 2792
Rule 3023
Rubi steps
\begin {align*} \int \frac {(a+b \sin (e+f x))^3}{(c+d \sin (e+f x))^{3/2}} \, dx &=\frac {2 (b c-a d)^2 \cos (e+f x) (a+b \sin (e+f x))}{d \left (c^2-d^2\right ) f \sqrt {c+d \sin (e+f x)}}-\frac {2 \int \frac {\frac {1}{2} \left (2 b (b c-a d)^2-a d \left (\left (a^2+b^2\right ) c-2 a b d\right )\right )+\frac {1}{2} \left (a^2 b c d-b^3 c d-a^3 d^2-a b^2 \left (2 c^2-3 d^2\right )\right ) \sin (e+f x)+\frac {1}{2} b \left (6 a b c d-3 a^2 d^2-b^2 \left (4 c^2-d^2\right )\right ) \sin ^2(e+f x)}{\sqrt {c+d \sin (e+f x)}} \, dx}{d \left (c^2-d^2\right )}\\ &=\frac {2 (b c-a d)^2 \cos (e+f x) (a+b \sin (e+f x))}{d \left (c^2-d^2\right ) f \sqrt {c+d \sin (e+f x)}}+\frac {2 b \left (6 a b c d-3 a^2 d^2-b^2 \left (4 c^2-d^2\right )\right ) \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{3 d^2 \left (c^2-d^2\right ) f}-\frac {4 \int \frac {-\frac {1}{4} d \left (3 a^3 c d+9 a b^2 c d-9 a^2 b d^2-b^3 \left (2 c^2+d^2\right )\right )+\frac {1}{4} \left (9 a^2 b c d^2-3 a^3 d^3-9 a b^2 d \left (2 c^2-d^2\right )+b^3 \left (8 c^3-5 c d^2\right )\right ) \sin (e+f x)}{\sqrt {c+d \sin (e+f x)}} \, dx}{3 d^2 \left (c^2-d^2\right )}\\ &=\frac {2 (b c-a d)^2 \cos (e+f x) (a+b \sin (e+f x))}{d \left (c^2-d^2\right ) f \sqrt {c+d \sin (e+f x)}}+\frac {2 b \left (6 a b c d-3 a^2 d^2-b^2 \left (4 c^2-d^2\right )\right ) \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{3 d^2 \left (c^2-d^2\right ) f}-\frac {\left (b \left (18 a b c d-9 a^2 d^2-b^2 \left (8 c^2+d^2\right )\right )\right ) \int \frac {1}{\sqrt {c+d \sin (e+f x)}} \, dx}{3 d^3}-\frac {\left (9 a^2 b c d^2-3 a^3 d^3-9 a b^2 d \left (2 c^2-d^2\right )+b^3 \left (8 c^3-5 c d^2\right )\right ) \int \sqrt {c+d \sin (e+f x)} \, dx}{3 d^3 \left (c^2-d^2\right )}\\ &=\frac {2 (b c-a d)^2 \cos (e+f x) (a+b \sin (e+f x))}{d \left (c^2-d^2\right ) f \sqrt {c+d \sin (e+f x)}}+\frac {2 b \left (6 a b c d-3 a^2 d^2-b^2 \left (4 c^2-d^2\right )\right ) \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{3 d^2 \left (c^2-d^2\right ) f}-\frac {\left (\left (9 a^2 b c d^2-3 a^3 d^3-9 a b^2 d \left (2 c^2-d^2\right )+b^3 \left (8 c^3-5 c d^2\right )\right ) \sqrt {c+d \sin (e+f x)}\right ) \int \sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}} \, dx}{3 d^3 \left (c^2-d^2\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {\left (b \left (18 a b c d-9 a^2 d^2-b^2 \left (8 c^2+d^2\right )\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}}\right ) \int \frac {1}{\sqrt {\frac {c}{c+d}+\frac {d \sin (e+f x)}{c+d}}} \, dx}{3 d^3 \sqrt {c+d \sin (e+f x)}}\\ &=\frac {2 (b c-a d)^2 \cos (e+f x) (a+b \sin (e+f x))}{d \left (c^2-d^2\right ) f \sqrt {c+d \sin (e+f x)}}+\frac {2 b \left (6 a b c d-3 a^2 d^2-b^2 \left (4 c^2-d^2\right )\right ) \cos (e+f x) \sqrt {c+d \sin (e+f x)}}{3 d^2 \left (c^2-d^2\right ) f}-\frac {2 \left (9 a^2 b c d^2-3 a^3 d^3-9 a b^2 d \left (2 c^2-d^2\right )+b^3 \left (8 c^3-5 c d^2\right )\right ) E\left (\frac {1}{2} \left (e-\frac {\pi }{2}+f x\right )|\frac {2 d}{c+d}\right ) \sqrt {c+d \sin (e+f x)}}{3 d^3 \left (c^2-d^2\right ) f \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}-\frac {2 b \left (18 a b c d-9 a^2 d^2-b^2 \left (8 c^2+d^2\right )\right ) F\left (\frac {1}{2} \left (e-\frac {\pi }{2}+f x\right )|\frac {2 d}{c+d}\right ) \sqrt {\frac {c+d \sin (e+f x)}{c+d}}}{3 d^3 f \sqrt {c+d \sin (e+f x)}}\\ \end {align*}
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Mathematica [A] time = 2.05, size = 311, normalized size = 0.86 \[ \frac {2 \left (\frac {\sqrt {\frac {c+d \sin (e+f x)}{c+d}} \left (d^2 \left (-3 a^3 c d+9 a^2 b d^2-9 a b^2 c d+b^3 \left (2 c^2+d^2\right )\right ) F\left (\frac {1}{4} (-2 e-2 f x+\pi )|\frac {2 d}{c+d}\right )+\left (-3 a^3 d^3+9 a^2 b c d^2+9 a b^2 d \left (d^2-2 c^2\right )+b^3 \left (8 c^3-5 c d^2\right )\right ) \left ((c+d) E\left (\frac {1}{4} (-2 e-2 f x+\pi )|\frac {2 d}{c+d}\right )-c F\left (\frac {1}{4} (-2 e-2 f x+\pi )|\frac {2 d}{c+d}\right )\right )\right )}{(c-d) (c+d)}-\frac {d \cos (e+f x) \left (3 a^3 d^3-9 a^2 b c d^2+9 a b^2 c^2 d+b^3 \left (c d^2-4 c^3\right )+b^3 d \left (d^2-c^2\right ) \sin (e+f x)\right )}{d^2-c^2}\right )}{3 d^3 f \sqrt {c+d \sin (e+f x)}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.56, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (3 \, a b^{2} \cos \left (f x + e\right )^{2} - a^{3} - 3 \, a b^{2} + {\left (b^{3} \cos \left (f x + e\right )^{2} - 3 \, a^{2} b - b^{3}\right )} \sin \left (f x + e\right )\right )} \sqrt {d \sin \left (f x + e\right ) + c}}{d^{2} \cos \left (f x + e\right )^{2} - 2 \, c d \sin \left (f x + e\right ) - c^{2} - d^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \sin \left (f x + e\right ) + a\right )}^{3}}{{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 5.20, size = 1398, normalized size = 3.87 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \sin \left (f x + e\right ) + a\right )}^{3}}{{\left (d \sin \left (f x + e\right ) + c\right )}^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (a+b\,\sin \left (e+f\,x\right )\right )}^3}{{\left (c+d\,\sin \left (e+f\,x\right )\right )}^{3/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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